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| If you haven't bothered to memorize precedents rules, there are two ways you might interpret the math below. If you interpret it one way, total_cost is 16. If you interpret it the other way, total_cost is _____. | total_cost = 1 + 3 * 4 | 13 | ^ *13 *$ |
| What is the value of total_cost? | total_cost = 1 + (3 * 4) | 13 | ^ *13 *$ |
| Rewrite this so total_cost is 16. | total_cost = 1 + 3 * 4 | total_cost = (1 + 3) * 4 | total_cost `= `(`1 `+ `3`) `* `4 |
| Rewrite this so total_cost is 13. | total_cost = 1 + 3 * 4 | total_cost = 1 + (3 * 4) | total_cost = 1 + (3 * 4) |
| Rewrite the following statement to force this order: First, multiply 2 by 4. Then add 4 and 2. Then multiply the first result by the second result. | x = 2 * 4 * 4 + 2 | x = (2 * 4) * (4 + 2) | ^ *x = \(2 \* 4\) \* \(4 \+ 2\) *$ |
| Rewrite the following statement to force this order: First, multiply 2 by 4. Then multiply that result by 4. Then add 2. | x = 2 * 4 * 4 + 2 | x = ((2 * 4) * 4) + 2 | ^ *x = \(\(2 \* 4\) \* 4\) \+ 2 *$ |
| Rewrite the following statement to force this order: First, multiply 2 by 4 by 4. Then add 2. | x = 2 * 4 * 4 + 2 | x = (2 * 4 * 4) + 2 | ^ *x = \(2 \* 4 \* 4\) \+ 2 *$ |
| Rewrite the following statement to force this order: First divide 5 by 7. Then subtract 1 from y. Then multiply the first result by the second result. | x = 5 / 7 * y - 1 | x = (5 / 7) * (y - 1) | ^ *x = \(5 / 7\) \* \(y - 1\) *$ |
| Rewrite the following statement to force this order: Subtract 1 from y. Then multiply that result by 7 for a second result. Then divide 5 by this second result. | x = 5 / 7 * y - 1 | x = 5 / (7 * (y - 1)) | ^ *x = 5 / \(7 \* \(y - 1\)\) *$ |
| Rewrite the following statement to force this order: Divide 5 by 7. Then multiply that result by y. Then subtract 1. | x = 5 / 7 * y - 1 | x = ((5 / 7) * y) - 1 | ^ *x = \(\(5 / 7\) \* y\) - 1 *$ |
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above your code. If you've coded correctly, the number 60 will display in the right-hand panel. (You can click Instructions at the top of the right-hand panel to see the correct code.)